At a certain time a particle had a speed of 48 m/s in the positive x direction, and 4.5 s later its speed was 92 m/s in the opposite direction. What was the average acceleration of the particle during this 4.5 s interval?

Explanation:

The acceleration of an object is the rate of change of velocity of the object.

Mathematically, it is calculated as:

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

Acceleration is a vector, so it is important to also take into account the direction of the velocity.

For the particle in this problem, we have:

u = +48 m/s is the initial velocity (positive direction)

v = -92 m/s is the final velocity (negative direction)

t = 4.5 s is the time interval

Therefore, the average acceleration is

You can calculate the distance and the amount of time it takes the child to throw the stones and the amount of force he is using.

Explanation: