At a given instant in time, a 18-kg rock is observed to be falling with an acceleration of 7.75 m/s2. what is the magnitude and direction of the gravitational force on the rock?
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Ответ:
36.9 N
Explanation:
m = 18 kg
a = 7.75 m/s^2
g = 9.8 m/s^2
F = mg - ma = 18 (9.8 - 7.75)
F = 18 x 2.05 = 36.9 N
The gravitational force acting on the rock is 36.9 N.
Ответ:
thanks for the free points
Step-by-step explanation: