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20.03.2020 •
Physics
At some distance from a point charge, the electric potential is 635.0 V and the magnitude of the electric field is 189.0 N/C. Find the distance from the charge. The value of the Coulomb constant is 8.98755 × 109 N · m2 /C 2 and the acceleration due to gravity is 9.81 m/s 2 . Answer in units of m.
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Ответ:
The distance from the charge is 3.35 m.
Explanation:
Given that,
Electric potential, V = 635 V
Magnitude of electric field, E = 189 N/C
We need to find the distance from the charge. We know that the relation between electric field and electric potential is given by :
d is the distance from charge
So, the distance from the charge is 3.35 m. Hence, this is the required solution.
Ответ:
0.33 m/s
Explanation:
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