connermichaela
28.06.2019 •
Physics
Atruck drives up a hill with a 15 incline. if the truck has a constant speed of 22m/s, what are the horizontal and vertical components of the trucks velocity
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Ответ:
a. The horizontal component of the truck's velocity is 5.69 m/s.
b. The vertical component of the truck's velocity is 21.25 m/s.
Given the following data:
Angle of inclination = 15°Velocity of truck= 22 m/sTo find both the horizontal and vertical components of the truck's velocity:
a. To find the horizontal component of the truck's velocity:
Mathematically, the horizontal component of velocity is given by the formula:
Horizontal component, Vy = 5.69 m/s
b. To find the vertical component of the truck's velocity:
Mathematically, the vertical component of velocity is given by the formula:
Vertical component, Vx = 21.25 m/s
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Ответ:
speed of truck (v) = 22 m/s ,
angle of hill (Θ) =15°
Find
Vertical component (Fv) = ?
Harizontal component (Fh) =?
Vertical component (Fh) = V cosΘ
= 22. cos 15
= 21.25 m/s.
Harizontal component (Fv) = V sinΘ
= 22. sin 15
= 5.69 m/s.
Ответ:
F=ma
m=5kg
a=54m/s^2
F=(5kg)(54m/s^2)=270N