Avertical electric field of magnitude 1.85 x 10^4 n/c exists above the earth's surface on a day when a thunderstorm is brewing. a car with a rectangular size of 6.00 m by 3.00 m is traveling along a dry gravel roadway sloping downward at 19.0°. determine the electric flux through the bottom of the car.

The electric flux through the car's bottom is

Solution:

As per the question:

Magnitude of vertical Electric field,

The area of the rectangular surface of the car,

Downward slope at an angle,

Now, the electric flux, is given by:

Now, substituting the appropriate values in the above formula:

1898.94 meters

Explanation:

Use kinematics.  First, we need to use the equation v(f) = v(i) + at.  The final velocity is 19 m/s, the initial velocity is 2 m/s, and the time is 120 seconds (it must be in seconds, so do 3 minutes*60).  19=2+a(180), solve for acceleration.

After solving, the acceleration equals .094 m/s².  Next, we need to find the distance, so we will use the kinematics equation v(f)² = v(i)² + 2ad.  Final velocity is 19 m/s, initial is 2 m/s, and the acceleration is .094 m/s².  19²=2²+2(.094)(d), solve for distance.

Distance = 1898.94 meters.