Aviolin string tuned to 485.0 hz is found to exhibit 2.6 beats per second with a guitar string. the guitar string is then tightened, and the beat frequency is found to increase. what was the original frequency of the guitar string? (enter your answer to one decimal place.)

Explanation:

It is given that,

Frequency of violin string tuned to,

Beat frequency,

Number of beats per second is given by :

Either or

When the guitar string is tightened, and the beat frequency is found to increase, then the original frequency will decrease.

So, the original frequency of the guitar string is 482.4 Hz. Hence, this is the required solution.

Particle A with charge q and mass ma and particle B with charge 2q and mass mb, are accelerated from rest by a potential difference AV and subsequently deflected by a uniform magnetic field into semicircular paths. ... The direction of the magnetic field is perpendicular to the velocity of the particle.