Awater tank in the shape of an inverted right circular cone that has a height of 12 ft and a base radius 6ft. if water is being pumped into the tank at a rate of 10 ft cubed per min , find the rate at which the water level is rising when the level of the water is 3 ft deep
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Ответ:
Explanation:
Given that
h= 12 ft
r= 6 ft
h= 2 r
r=h/2
We know that volume of cone given as
Now by putting the values
r=h/2
Given that when h= 3 ft
By putting the values
So the rate at which the water level is rising is 1.41 ft/min
Ответ:
3x 10^10
Explanation:
(9.9 x 10^4)= 99 000
(3.3 x 10^-6)= 0.0000033
99 000 / 0.0000033 = 3x 10^10