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candaceblanton
05.08.2019 •
Physics
Awye-delta transformer has a turns ratio of 2: 1. it has a secondary phase to phase voltage of 480 v. the secondary is connected to a wye-connected three-phase resistive load of 50 ohms in each phase. how much current flow is there in each load resistor?
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Ответ:
4.8 A
Explanation:
We have given phase voltage that is 480 volt
We know that for transformer
where
are phase voltage and
are primary and secondary turns respectively
We have given 480 v as phase voltage
So![\frac{480}{v_2}=\frac{2}{1}](/tpl/images/0171/8022/618cc.png)
We have given that![z_{phase}=50\ ohm](/tpl/images/0171/8022/4ce33.png)
so current through each load resistor that phase current![i=\frac{v_{phase}}{z_{phase}}=\frac{240}{50}=4.8\ A](/tpl/images/0171/8022/835e2.png)
Ответ: