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Yomarie1104
22.09.2019 •
Physics
(b) what would the radius of the earth be if its matter were compressed to the same density as that of a carbon nucleus? (the earth’s average radius is 6.4 103 km, and its average density is 5.5 g cm 3.)
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Ответ:
Volume of Earth = 4/3π(6.4×10³ km * 100,000 cm/1 km)³
Volume = 1.098×10²⁷ cm³
Mass of Earth = 5.5 g/cm³ * 1.098×10²⁷ cm³
Mass of Earth = 6.039×10²⁷ g
Then, we equate this with the density of carbon nucleus.
2.01×10¹⁵ g/cm³ = 6.039×10²⁷ g/V
V = 3×10¹² cm³
Let's equate this to the volume of a sphere of the Earth:
V = 3×10¹² cm³ = 4/3*πr³
r = 40.18 cm
The radius of the Earth should be reduced to 40.18 cm.
Ответ:
Ответ:
59,9334м / час
Пояснение:
Используя формулу Скорость = Расстояние / Время
Время = Расстояние / скорость
Если автомобиль использовал скорость 20м / час на первом этапе своего пути и преодолевает одну треть расстояния, общее время, затраченное автомобилем, составит;
Время = (д / 3) ÷ 20
Т1 = d / 3 × 1/20
T1 = d / 60 часов
Для второй части путешествия:
Если он использовал скорость 36 км / ч до конца пути
Расстояние = 1- d / 3 = 2d / 3
Скорость = 36000 м / час {1 км = 1000 м}
Время, затраченное на это путешествие = 2д / 3 ÷ 36000
Т2 = 2d / 3 × 1/36000
Т2 = 2d / 108000
T2 = d / 54000
Общее время, затраченное на всю поездку = d / 60 + d / 54000
Общее расстояние = d / 3 + 2d / 3
Общее расстояние = d
Средняя пройденная скорость за весь путь = d / (d / 60 + d / 54000)
= d / (900d + d) / 54000
= d / {901d / 54000}
= d × 54000 / 901d
= 54000/901
= 59,9334м / час
Отсюда средняя пройденная скорость за весь путь составляет 59,9334 м / час