Physics: Bare free charges do not remain stationary when close together. to illustrate this, calculate the acceleration of two isolated protons separated by 3.73 nm (a typical distance between gas atoms). (enter the magnitude in m/s2.)

Yes, you need to convert unless the question specifically requires km/h....

Bare free charges do not remain stationary when close

Ответ:

dudedan05

02.01.2022

Physics

Acceleration, $a=9.91\times 10^{15}\ m/s^2$

Explanation:

It is given that,

Separation between the protons, $r=3.73\ nm=3.73\times 10^{-9}\ m$

Charge on protons, $q=1.6\times 10^{-19}\ C$

Mass of protons, $m=1.67\times 10^{-27}\ kg$

We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

$ma=\dfrac{kq^2}{r^2}$

$a=\dfrac{kq^2}{mr^2}$

$a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}$

$a=9.91\times 10^{15}\ m/s^2$

So, the acceleration of two isolated protons is $9.91\times 10^{15}\ m/s^2$ . Hence, this is the required solution.

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Bare free charges do not remain stationary when close together. to illustrate this, calculate the acceleration of two isolated protons separated by 3.73 nm (a typical distance between gas atoms). (enter the magnitude in m/s2.)

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