Batman (mass = 96.1 kg) jumps straight down from a bridge into a boat (mass = 458 kg) in which a criminal is fleeing. The velocity of the boat is initially +11.3 m/s. What is the velocity of the boat after Batman lands in it?

The velocity of the boat after the batman lands in it is +9.26 m/s

Explanation:

Applying the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

Note: The collision between the Batman and the boat is an inelastic collision.

m'u'+mu = V(m+m') Equation 1

Where m' = mass of the Batman, u' = initial velcoity of the batman, m = mass of the boat, u = initial velocity of the boat, V = common velocity.

make V the subject of equation 1

V = (m'u'+mu)/(m+m') Equation 2

Given: m' = 96.1 kg, u' = 0 m/s, m = 458 kg, u = +11.3 m/s.

Substitute these values into equation 2

V = [(96.1×0)+(458×11.2)]/(96.1+458)

V = 5129.6/554.1

V = +9.26 m/s

Therefore,

Priya's way is correct to  solve the equation.

Other person Strategyis Equation is

Step-by-step explanation:

Given:

Jada and Priya are trying to solve the equation,

For Jada way of calculation :

I think we should multiply each side by 32 because that is the reciprocal of 23.

Also Reciprocal of 23 is

We have

...Which is INCORRECT

For Priya way of calculation :

I think we should add -23 to each side because that is the opposite of 23.

We have

plus minus= minus , (+ - = - )

23 will get cancelled and she will get "x"

...Which is CORRECT

Hence Priya's way is correct to  solve the equation.

The other Person strategy to solve will be:

I think we should subtract 23 to each side because that is the opposite of 23.

We have

...Which is also CORRECT.

Therefore,

Priya's way is correct to  solve the equation.

Other person Strategyis Equation is