roadrnr5183
27.07.2020 •
Physics
Bumper car A (331 kg) moving east at 3.87 m/s hit stationary car B (208 kg). After, the car A moves .88 m/s east. What is the velocity of car B?
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Ответ:
Ub = 221.99m/s
Explanation:
(Ma x Ua)+(Mb x Ub) = (Ma + Mb)V
(331 x 3.87)+(208 x Ub) = (331 + 208)88
(1257.8) + (208 x Ub) = 47432
(208 x Ub) = 47432 - 1257.8
(208 x Ub) = 46174.2
Ub = 46174.2/208 = 221.99m/s
Ub = 221.99m/s
Ответ:
Eg- Gravitational forces acts downwards due to the earth's pull.