Calculate the acceleration due to gravity
at a height of 300 km from the surface of
the Earth. (M = 5.98 x10²4 kg, R = 6400
km).
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Ответ:
8.8854 m/s²
Explanation:
Using the relation :
g = GM / (r + R)^2
G = Gravitational constant = 6.67 * 10^-11
M = mass of earth = 5.98 * 10^24 kg
r = distance = 300 km
R = Radius of earth 6400 km
g = (6.67 * 10^-11 * 5.98 * 10^24) / ((6400+300) * 10^3)^2
g = (6.67 * 5.98 * 10^(-11 + 24)) / (6700 * 10^3)^2
g = (39.8866 * 10^13) / 44890000 * 10^6
g = 0.000000888540 * 10^(13 - 6)
g = 0.000000888540 * 10^7
g = 8.8854 m/s²
Ответ:
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