Physics: Calculate the electric field acting on the electron in a hydrogen atom due to the proton in the nucleus the radius of the orbit of the electron is 5.3×10^-11

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Calculate the electric field acting on the electron

weeblordd

02.08.2021

$F=-8.2*10^{-8}N$

Explanation:

From the question we are told that:

Radius $r=5.3*10^{-11}$

Where

Proton Charge $q_1=1.6*10^{-19}C$

Charge of Electron $q_2=-1.6*10^{-19}C$

Generally the equation for Coulomb's Law is mathematically given by

$F=\frac{9*10^9(q_1)(q_2)}{r^2}$

$F=\frac{9*10^9(1.6*10^{-19}C)(-1.6*10^{-19}C)}{5.3*10^{-11}}$

$F=-8.2*10^{-8}N$

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