Physics: Calculate the pressure in a 212 liter tank containing 23.3 kg of argon gas at 25°c

Calculate the pressure in a 212 liter tank containing

Ответ:

ianim207

13.03.2022

Physics

First of all, let's find the number of moles of the gas.

The molar mass of argon is M_m=40 g/mol=0.40 kg/mol

. Since we have m=23.3 kg

of gas, the number of moles is
$n= \frac{m}{M_m}= \frac{23.3 kg}{0.40 kg/mol}=58.3 mol$

Now we can use the ideal gas law to calculate the pressure of the gas:
pV=nRT

where
p is the pressure
V=212 L=0.212 m^3

is the volume
n=58.3 mol

is the number of moles
R=8.31 J/mol K

is the gas constant
$T=25^{\circ}+273=298 K$ is the absolute temperature

Rearranging the equation, we find
$p= \frac{nRT}{V}= \frac{(58.3 mol)(8.31 J/mol K)(298 K)}{0.212 m^3}=6.81 \cdot 10^5 Pa$

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Ответ:

beverlyamya

20.01.2023

Physics

It's dependent on the mass. You can fimd the force needed using the formula F = ma. Where F is force, m is mass of the cart and a is the acceleration (0.9m/s^2). The heavier it is the more force you are going to need. Remember unit of force is N

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Calculate the pressure in a 212 liter tank containing 23.3 kg of argon gas at 25°c

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