Calculate the value of δe in joules for a system that loses 115 j of heat and has 150 j of work performed on it by the surroundings.

L = 2.83 J.s

Explanation:

The formula for the angular momentum of the stone is given as follows:

L = mvr

where,

L = angular momentum of the stone  = ?

m = mass of the stone = 0.1 kg

v = linear velocity of the stone = rω

r = radius of circular path = 1.5 m

ω = angular speed of the stone = (2 rev/s)(2π rad/1 rev) = 4π rad/s

Therefore,

L = mvr = m(rω)r

L = mr²ω

using values, we get:

L = (0.1 kg)(1.5 m)²(4π rad/s)

L = 2.83 J.s