Coherent light of frequency 6.32×1014 hz passes through two thin slits and falls on a screen 87.0 cm away. you observe that the third bright fringe occurs at 3.16 cm on either side of the central bright fringe.
at what distance from the central bright fringe will the third dark fringe occur?
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Ответ:
Explanation:
The interference pattern for a two slit system is given by
d sin θ = m λ constructive interference
d sin θ= (m + ½) λ destructive interference
In general and also in this case the screen is far from the slits, so the TT-free can approach the TT
tan θ = y / L
Let's replace
d y / L = m λ constructive interference
d y / L = (m + ½) λ destructive interference
Let's start when there is constructive interference
They give us the frequency of light, let's find the wavelength
c = λ f
λ = c / f
λ = 3 10⁸ / 6.32 10¹⁴
λ = 4.7468 10⁻⁷ m
Let's take the opportunity to reduce the SI system
L = 87 cm = 0.87 m
y = 3.16 cm = 0.0316 m
Now we can find the separation of the slits
d = m λ L / Y
d = 3 4.7468 10⁻⁷ 0.87 / 0.0316
d = 3.92 10⁻⁵ m
We already have all the data, now let's use the destructive interference equation and find![y_{osc}](/tpl/images/0384/0409/7f706.png)
d
/ L = (m + ½) λ
Ответ:
13.07m/s2 down
Explanation:
I think the equation would be
Fnet/m=a
since tension is the only force mensioned that means that
170N/13.0kg=13.07 m/s2 down
acceleration is down