Physics: Compare the energy required to warm 1kg of water from 0ºc to 100ºc, to energy required to turn 1kg of water from liquid to vapor at 100ºc. a) warming the water requires more energy b) vaporizing the water requires more energy c) both processes require the same amount of energy

I also agree that carbons are opaque because it is a solid non metal.If it was a carbon dioxide then it might have been transparent...

Compare the energy required to warm 1kg of water

rlafferty5604

31.12.2021

The correct answer is Option a.

Explanation:

The chemical equation for warming of water from 0°C to 100°C follows:

$H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)$

To calculate the amount of heat absorbed, we use the equation:

$q_1=m\times C_{p,l}\times (T_{2}-T_{1})$

where,

q_1 = amount of heat absorbed = ?

$C_{p,l}$ = specific heat capacity = 4.186 J/g °C

m = mass of water = 1 kg = 1000 g (Conversion factor: 1 kg = 1000 g)

T_2 = final temperature = 100^oC

T_1 = initial temperature = 0^oC

Putting all the values in above equation, we get:

$q_1=1000g\times 4.186J/g^oC\times (100-0)^oC=418600J$

The chemical equation for vaporization of water follows:

$H_2O(l)\rightarrow H_2O(g)$

To calculate the amount of heat released, we use the equation:

$q_2=m\times L_v$

where,

q_2 = amount of heat absorbed = ?

m = mass of water = 1 kg

L_f = latent heat of vaporization = 2260000 J/kg

Putting all the values in above equation, we get:

$q_2=1kg\times 2260000J/kg=2260000J$

From the calculations above, we get that q_1q_2

So, the warming of water requires more energy.

Hence, the correct answer is Option a.

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