bekahmiller2001
19.12.2019 •
Physics
Compute the tensile strength and ductility (%elongation, el) of a cylindrical copper rod if it is cold worked such that the diameter is reduced from 15.2 mm to 12.2 mm. note: materials become harder or stronger as they are plastically deformed. this is called as strain hardening. it is also called as work hardening and cold working. %cw
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Ответ:
Therefore, as cold work is increased, yield strength increases, Tensile strength increases and Ductility (%EL) decrease
If we trace the intersection point between the X and Y axis,
We then derive %EL at 7%
Considering the given data, The %CW IS 35.5 and approximately 35.6
Explanation:
Recalling the formula for cold working ( %CW),
We have, dr1² - dr2² ÷ dr1² × 100
Where dr1 = Initial Diameter of the copper rod 15.2
dr2 = Reduced diameter of the copper rod 12.2
Now, substituting the values into the equation,
We have, 15.2² - 12.2² ÷ 15.2² × 100
Now if we apply the principle of BODMAS, where
B= bracket, O = off, D= division, M = Multiplication, A= Addition, S= Subtraction.
Considering this principle in solving the substituted vales,
We have,
%CW = 231.04 - 148.84 ÷ 231.04 × 100
=82.2 ÷231.04 ×100
82.2 ×100 = 8220
Therefore, 8220/231.04
%CW = 35.6
Now, for the Percentage elongation from the graph,
Let us plot a graph of Ductility (% EL) against % Cold work
Where ductility is on the y axis and %cold work is on the x axis
On the y axis, we have 0, 20, 40, in accending order while on the x axis, we have 0, 20, 40, 60,
A downward slope toward positive x axis
If we trace the intersection point between the X and Y axis,
We then derive %EL at 7%
Therefore, as cold work is increased, yield strength increases, Tensile strength increases and Ductility (%EL) decrease
Ответ:
Explanation:
I would need the pic attachment for this question in-order to be able to attempt the question.