Consider a motor that exerts a constant torque of 25.0 nâ‹…m to a horizontal platform whose moment of inertia is 50.0 kgâ‹…m2. assume that the platform is initially at rest and the torque is applied for 12.0 rotations. neglect friction.
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Ответ:
W = 1884J
Explanation:
This question is incomplete. The original question was:
Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction.
How much work W does the motor do on the platform during this process? Enter your answer in joules to four significant figures.
The amount of work done by the motor is given by:
Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.
By using kinematics:
But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:
Now we can calculate the final velocity:
Finally, we calculate the total work:
Since the question asked to "Enter your answer in joules to four significant figures.":
W = 1884J
Ответ:
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