Determine the mass of the load hanging on the spring with a stiffness of 200 n / m if the extension of the spring is 0.5 cm

P. E=mgh

P. E=200

200=m x 10 X 0.005

200=m x 0.05

200/0.05=m

4000Kg=m

Hope it helps

4 m/s²

Explanation:

The formula used here:

F = ma

F is force (80 N)

m is mass (20 kg)

a is acceleration

Since we need to calculate acceleration we will arrange the formula:

a = F ÷ m

Now substitute the values and solve

a = 80 ÷ 20

a = 4

The proper unit for this acceleration is m/s²

So the object accelerates at 4 m/s²