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lucaszsanches
25.12.2019 •
Physics
Determine the mass of the load hanging on the spring with a stiffness of 200 n / m if the extension of the spring is 0.5 cm
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Ответ:
P. E=mgh
P. E=200
200=m x 10 X 0.005
200=m x 0.05
200/0.05=m
4000Kg=m
Hope it helps
Ответ:
4 m/s²
Explanation:
The formula used here:
F = ma
F is force (80 N)
m is mass (20 kg)
a is acceleration
Since we need to calculate acceleration we will arrange the formula:
a = F ÷ m
Now substitute the values and solve
a = 80 ÷ 20
a = 4
The proper unit for this acceleration is m/s²
So the object accelerates at 4 m/s²