Physics: Doc Brown has calculated that his Delorean can accelerate at a rate of 2.52 m/s/s. How far away must he and Marty stand to allow the car to accelerate from rest to a speed of 39.1 m/s?

The current flowing through the outer coils is Explanation:From the question we are told that The number of turn of inner coil is The radius of inner coil is The current flowing through the inner coil is The number of turn of outer coil is The radius of outer coil is For net magnetic field at the common center of the two coils to be zero the current flowing in the outer coil must be opposite to current flowing inner coil The magnetic field due to inner coils is...

Doc Brown has calculated that his Delorean can

Ответ:

Birlem101

02.02.2022

Physics

d = 303.33 m

Explanation:

Given that,

Acceleration of Doc Brown is 2.52 m/s²

The initial speed of Doc Brown is 0 as it was at rest.

Final speed of Doc Brown is 39.1 m/s

We need to find the distance between he and Marty. Let the distance is d. Using equation of motion as follows :

$v^2-u^2=2ad\\\\\text{Put u = 0}\\\\d=\dfrac{v^2}{2a}\\\\d=\dfrac{(39.1)^2}{2\times 2.52}\\\\d=303.33\ m$

So, the distance between he and Marty is 303.33 m.

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Ответ:

student0724

19.07.2021

Physics

The current flowing through the outer coils is

Explanation:

From the question we are told that

The number of turn of inner coil is $N _i = 110 \ turns$

The radius of inner coil is $r_i = 0.014 \ m$

The current flowing through the inner coil is $I_i = 9.0 \ A$

The number of turn of outer coil is $N_o = 160 \ turns$

The radius of outer coil is $r_o = 0.022\ m$

For net magnetic field at the common center of the two coils to be zero the current flowing in the outer coil must be opposite to current flowing inner coil

The magnetic field due to inner coils is mathematically represented as

$B_i = \frac{N_i \mu I}{2 r_i}$