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miabarrett8117
16.07.2021 •
Physics
Drag the tiles to the boxes to form correct pairs. The table shows the distances between a star and three celestial objects. Use the conversion factors to rewrite the distances in different, but equivalent units. Celestial Objects Distance from the Star object A 0.000001877 pc object B 30.06 AU object 778.3 million km Conversion factors: 1 AU = 1.5 x 108 km 1 light-year = 9.5 1012 km 1 parsec = 31 trillion km, or about 3.262 light-years distance to object A distance to object B distance to object C 0000145RC
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Ответ:
where v = transverse wave velocity, T = tension in the string, M = mass per unit length.
Explanation:
Dimensional analysis is where you just look at the units and see how they fit within each other.
In this case, all relationships are made using the MLT comparisons, where M stands for Mass, L stands for Length, and T stands for time.
For example, for velocity, we know the SI unit for velocity is [ms⁻¹] which is L¹T⁻¹, we can do the same thing for tension = [N = Kgms⁻²] = M¹L¹S⁻², and for the mass per unit length which we can think of as [Kgm⁻¹] = M¹L⁻¹.
If you play around a little with the powers, you can find a relationship:
since:
[L¹T⁻¹]² = L²T⁻² = M¹L¹T⁻² ÷ M¹L⁻¹ = M¹⁻¹L¹⁻⁽⁻¹⁾T⁻² = M⁰L²T⁻² = L²T⁻²