During a car accident, a 125kg driver is moving at 31m/s and in 1.5s is brought to rest by an inflating air bag. what is the magnitude of the change in momentum to the driver

Given:
velocity = 10.0 m/s.
The plane is 3520 m above the earth. The sky diver pulls his cord at 1760 m above the earth.
gravity = 9.8 m/s²

Δheight = initial height - final height = gt²/2 

time =√(2 • Δh/g) 
time =√{2 • (3520-1760)/9.8}
time =√{2 * 179.59 s²
time = √359.18
time = 18.95 s. 

s=vt=10•18.95=189.5m or 190m

The skydiver traveled 190m horizontally before pulling the cord.