Physics: During takeoff, an airplane climbs with a speed of 150 m/s at an angle of 45 degrees above the horizontal. the speed and direction of the airplane constitute a vector quantity known as the velocity. the sun is shining directly overhead. how fast is the shadow of the plane moving along the ground

During takeoff, an airplane climbs with a speed

Jaymiegrimes22

09.03.2022

106.1 m/s

Explanation:

The shadow of the plane is moving at the same velocity as the horizontal component of the airplane's velocity.

The horizontal component of the airplane's velocity is

$v_x = v cos \theta$

where

v = 150 m/s is the velocity of the airplane

$\theta=45^{\circ}$ is the angle between the airplane's velocity and the horizontal

Substituting,

$v_x = (150 m/s) cos 45^{\circ} = 106.1 m/s$

So, the shadow is moving at 106.1 m/s as well.

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