Physics: Find the center of mass (in cm) of a one-meter long rod, made of 50 cm of brass (density 8.44 g/cm3) and 50 cm of lead (density 11.3 g/cm3). (Assume the origin is at the midpoint of the rod, with the positive direction towards the part of the rod made of lead. Indicate the direction with the sign of your answer.)

Find the center of mass (in cm) of a one-meter

chriscendypierre56

22.01.2022

$\bar r = +3.622\,cm$

Explanation:

Let consider that both rods have uniform densities. The location of the center of mass is given by the following formula:

$\bar r = \frac{\rho_{brass}\cdot r_{brass}+\rho_{lead}\cdot r_{lead}}{\rho_{brass}+\rho_{lead}}$

$\bar r = \frac{(8.44\,\frac{g}{cm^{3}} )\cdot (-25\,cm)+(11.3\,\frac{g}{cm^{3}} )\cdot (+25\,cm)}{8.44\,\frac{g}{cm^{3}}+11.3\,\frac{g}{cm^{3}}}$

$\bar r = +3.622\,cm$

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eddsworldfrantic

02.03.2022

the displacement was 31

Explanation:

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