Find the displacement current through a parallel-plate capacitor. Assume that V is the voltage across the capacitor at any instant. Express your answer in terms of the variables C and dV/dt.

displacement current; i_d = C(dV/dt)

Explanation:

Let i_d be the displacement current

Thus,

i_d = ε_o(dΦ/dt)

We know that flux Φ = EA

Thus,

i_d = ε_oA(dE/dt)

We also know that E = V/d

Thus, i_d = ε_oA(d(V/d)/dt)

i_d = ε_o(A/d)(dV/dt)

Now, capacitance has a formula of;

C = ε_o(A/d)

Thus,

i_d = C(dV/dt)

0.8 second

Explanation:

Given data

Speed v=6.7m/s

Deceleration = - 8.3m/s²

Initial velocity u= 0m/s

We can solve for the distance covered upon breaking the speed using the expression

v=u +at

6.7=0-(8.3)t

6.7=8.3t

Divide both sides by 8.3

6.7/8.3=t

t=6.7/8.3

t=0.8 second