Physics: Find the force of attraction between a proton and an electron separated by a distance equal to the radius of the smallest orbit followed by an electron (5 x 10^-11 m) in a hydrogen atom

Find the force of attraction between a proton

Ответ:

woodfordmaliky

02.01.2022

Physics

The answer is $-9.239 \times 10^{-8}\ N =$

Explanation:

The definition of electric force between two puntual charges is

$F_e = \frac{K q_1 q_2}{d^2}$

where

$K = 9 \times 10^9\ Nm^2/C^2$ .

In this case,

$q_1 = e = 1.602\times 10^{-19}\ C$ ,

$q_2 = -e = -1.602\times 10^{-19}\ C$

and

$d = 5 \times 10^{-11}\ m$ .

So the force is

$F_e = -9.239 \times 10^{-8}\ N$

where the negative sign implies force of attraction.

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Ответ:

junielouwho

14.09.2020

Physics

Static Friction

It is the friction that exists between a stationary object and the surface on which it's resting.

Sliding friction

It is the resistance created by two objects sliding against each other.

Rolling friction:-

It is the force resisting the motion when a body rolls on a surface.

hope this helps x

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Find the force of attraction between a proton and an electron separated by a distance equal to the radius of the smallest orbit followed by an electron (5 x 10^-11 m) in a hydrogen atom

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