Find the time taken if the speed of a train increased rom 72km/h to 90km/h for 234km
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Ответ:
2.89 hours
Explanation:
given :
Vo = 72 km/h
Vt = 90 km/h
S = 234 km
find : the time taken (t) = ?
solution :
2.a.s = Vt² - Vo²
2.a.(234) = 90²- 72²
468.a = 8100 - 5184
= 2916
a = 2916/468 = 6.23 km/h²
so,
t = (Vt-Vo) /a
= (90-72)/ 6.23
= 18/ 6.23
= 2.89 hours
Ответ:
Explanation:
s = s₀ + v₀t + ½at²
Let s₀ = 0 be the position in km where acceleration starts,
Let t be in hours
a = (90 - 72) / t = 18/t km/hr²
234 = 0 + 72t + ½(18/t)t²
234 = 72t + 9t
234 = 81t
t = 2.88888... ≈ 2.89 hr
Ответ:
Yeet
Explanation: