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jordanmjdmary8898
16.03.2020 •
Physics
Four copper wires of equal length are connected in series. Their cross-sectional areas are 0.7 cm2 , 2.5 cm2 , 2.2 cm2 , and 3 cm2 . If a voltage of 145 V is applied to the arrangement, determine the voltage across the 2.5 cm2 wire.
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Ответ:
22.1 V
Explanation:
We are given that
Using![1cm^2=10^{-4} m^2](/tpl/images/0549/0922/3a18e.png)
We know that
In series
Substitute the values
Voltage across the 2.5 square cm wire=![IR=I\times \frac{\rho l}{A_2}](/tpl/images/0549/0922/ef36e.png)
Voltage across the 2.5 square cm wire=![\frac{145}{\rho l(2.62\times 10^4)}\times \frac{\rho l}{2.5\times 10^{-4}}=22.1 V](/tpl/images/0549/0922/7dbfa.png)
Voltage across the 2.5 square cm wire=22.1 V
Ответ: