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jvanegas6797
23.11.2019 •
Physics
Four particles, one at each of the four corners of a square with 2.0-m-long edges, are connected by massless rods. the masses are m1=m3=3.0 kg and m2=m4=4.0 kg. find the moment of inertia of the system about the z axis. (the z axis runs through m2, which is at the origin, m1 is on the y axis, and m3 is on the x axis. use the parallel-axis theorem and the result for problem 41 to find them moment of inertia of the four-particle system about an axis that passes through the center of mass and is parallel with the z axis. check your result by direct computation.
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Ответ:
Explanation:
The particles are in x-y plane with coordinates of masses as follows
m₂ at (0,0 ) m₁ at ( 0,2 ), m₄ at ( 2,2 ) and m₃ at (2,0 )
Moment of inertia about z axis
I_z = 0 + 3 x 2² + 4 x (2√2)² + 3 x 2²
= 12 + 32 + 12
= 56 kgm²
Now let us find out moment of inertia about axis through CM
According to theorem of parallel axis
I_z = I_g + m x r²
Here m is total mass that is 14 kg and r is distance between two axis which is √2 m
56 = I_g + 14 x (√2)²
I_g = 56 - 28
= 28 kgm²
We can directly compute I_g as follows
I_g = 4 x (√2)² +3 x (√2)² +4 x (√2)²+3 x (√2)²
= 8 +6 +8 +6
= 28 kgm²
So the result obtained earlier is correct.
Ответ: