G Problem 4. A 2000 kg railway freight car coasts at 4.4 m/s underneath a grain terminal, which dumps grain directly down into the freight car. If the speed of the loaded freight car must not go below 3.0 m/s, what is the maximum mass of grain that it can accept

2933 kg

Explanation:

Given

From the law of conservation of linear momentum, we know that

m(i)v(i) = m(f)v(f), where there is no external force acting on the system

m(i) = initial mass of the freight car system

m(f) = maximum mass of the freight car system

v(i) = initial linear velocity of the system

v(f) = final linear velocity of the system

2000 * 4.4 = m(f) * 3

3m(f) = 8800

m(f) = 8800 / 3

m(f) = 2933.3 kg

Therefore the maximum mass of grain that it can accept is 2933 kg

Is there a picture of it?