Gold, which has a density of 19.32 g/cm3, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber.
(a) If a sample of gold with a mass of 1.915 g, is pressed into a leaf of 7.331 μm thickness, what is the area of the leaf?
(b) If, instead, the gold is drawn out into a cylindrical fiber of radius 2.100 μm, what is the length of the fiber?
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Ответ:
a) 0.014 m2
b) 7.1 Km
Explanation:
Density = mass/volume
volume - mass/density
volume = 1.915 g/19.32 g/cm3 = 0.099 * 10^-6 m3
Volume = Area * thickness
thickness = 7.331 * 10^-6 m
Area = Volume/thickness
Area= 0.099 * 10^-6 m3/7.331 * 10^-6 m
Area= 0.014 m2
b. Volume = πr^2h
h = volume/πr^2
h = 0.099 * 10^-6 m3/3.142 * ( 2.100 * 10^-6)^2
h = 0.099 * 10^-6 m3/3.142 *4.41 * 10^-12
h = 7.1 * 10^3 m
h = 7.1 Km
Ответ:
The answer is below
Explanation:
Density is the ratio of mass to volume. It is given by the formula:
Density = mass / volume
a) Density of gold = 19.32 g/cm³
Mass of gold = 1.915 g
Therefore the volume (V) occupied by the gold is:
Density = mass / volume
19.32 = 1.915 / volume
volume = 1.915 / 19.32 = 0.0991 cm³
The volume of the leaf = Area * thickness
Volume of leaf = Area * (7.331 * 10⁻⁴ cm)
Volume of gold = volume of leaf
0.0991 cm³ = Area * (7.331 * 10⁻⁴ cm)
Area = 135.2 cm²
b) The volume of the cylinder = πr²h = π(2.1 * 10⁻⁴ cm)² * h
Volume of gold = volume of cylinder
0.0991 cm³ = π(2.1 * 10⁻⁴ cm)² * h
h = 0.0991 cm³ / [π(2.1 * 10⁻⁴ cm)²]
h = 340617 cm
Ответ: