Hegelich a particle undergoes two displacements. the first has a magnitude of 163 cm and makes an angle of 128 ◦ with the positive x axis. the resultant displacement has a magnitude of 176 cm and is directed at an angle of 36.8 ◦ to the positive x axis. find the magnitude of the second displacement. answer in units of cm

Explanation:

First displacement is given as

= 163 cm at 128 degree

so we have

Now the resultant displacement is given as

= 176 cm at 36.8 degree

so we have

now we know that

so magnitude of the above displacement is given as

For iron, T2 = 40.4 degree C

For copper, T2 = 68.89 degree C

Explanation:

For iron:

m = 1.9 kg, T1 = 24 C, Q = 14 kJ = 14000 J, c = 0.450 J / g C = 450 J / Kg C

Let T2 be the final temperature of iron.

Q = m x c x (T2 - T1)

14000 = 1.9 x 450 x (T2 - 24)

T2 = 40.4 degree C

For copper:

m = 810 g = 0.81 kg, T1 = 24 C, c = 0.385 J/ g C = 385 J / Kg C, Q = 14 KJ

Let T2 be the final temperature of copper

Q = m x c x (T2 - T1)

14000 = 0.81 x 385 x (T2 - 24)

T2 = 68.89 degree C