HELP ME PLEASE If an object is placed under a force of 20 N, it accelerates at a rate of 5 m/s^2. If the force is increased to 55 N, what is the new acceleration? a 13.75 kg b 7.25 kg c 21.10 kg d 5.65 kg

Given :

The diagram below shows a force of 5N acting on an object P at an angle of 30° to the horizontal.

To Find :

By drawing appropriate lines on the diagram using a ruler to determine:

a.)The horizontal component of the 5N force.

b.)The vertical component of the 5N force.

Solution :

Horizontal component is given by :

=F cos θ

=5 cos 30°

= 5×0.866

= 4.33 N

Vertical component is given by :

= F sin θ

= 5 sin 30°

= 5×0.5

= 2.5 N

Therefore, horizontal and vertical component are 4.33 N and 2.5 N.

Hence, this is the required solution.