How does water flowing over a waterfall involve both kinetic energy and potential energy?
plz i have a test tommorrow! ttott
Solved
Show answers
More tips
- S Style and Beauty How to Choose the Perfect Hair Color?...
- C Computers and Internet Best iPad Games: Our Opinion...
- A Animals and plants Man s Best Friend: Which Dog Breed Is the Most Friendly?...
- H Health and Medicine 10 Simple Techniques on How to Boost Your Mood...
- G Goods and services How to Choose the Right High Chair for Your Baby?...
- S Style and Beauty Learn how to tie a keffiyeh on your head like a pro...
- S Style and Beauty How to braid friendship bracelets?...
Answers on questions: Physics
- P Physics One 4 kg bowling ball traveling right at 1 m/s collides with a stationary 2 kg bowling ball. They stick together and move away. What is the final velocity of the two...
- M Mathematics Help fast please it s timed...
- S Spanish Si va a un viaje de paseo ¿Qué dispositivos electrónicos lleva con usted y por qué?...
- L Law 17. The Constitution says that the Congress must meet a. at least once every two years b. at least once each year c. for a total of six months, every other year d. only...
Ответ:
Explanation:
We have seen at the top of the waterfall, water has a certain speed. So definitely at the top water has a certain amount of kinetic energy.
And also the higher end of the water fall also has a certain certain elevation from the ground level. So water must also has a certain potential energy before taking the fall.
What happens when it falls is that the amount of potential energy it had reduces as it's elevation reduces. and kinetic energy it had increases and we can see the water drops speed up.
This phenomenon can be explained by the law of conservation of energy.
It can be applied as,
The K.E. + P.E. the water had at the top = The K.E. + P.E. the water had at the bottom.
So you can see as elevation decrease, potential energy decrease, kinetic energy increase and total energy conserved.
Ответ:
Explanation:
v=?, u=0, a=?, S=22m.
Using the formula, S=ut+½at²
22={0×5}+(½.a.5²)
22=½.a.5²
a=44/25 = 1.76m/s².
Therefore, net force = work done = ma = 48×1.76 = 84.48N.
therefore, power = work done/time = 84.48/5 = 16.896W.
hope this helps you.