keshan3000
25.05.2021 •
Physics
One 4 kg bowling ball traveling right at 1 m/s collides with a stationary 2 kg bowling ball. They stick together and move away. What is the final velocity of the two bowling balls stuck together?
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Ответ:
0.6m/s
Explanation:
Given data
M1= 4kg
U1= 1m/s
M2= 2kg
U2= 0m/s
The system experiences an inelastic collision, the expression for inelastic collision is
M1U1+ M2U1= (M1+M2)V
Subsitute
4*1+ 2*0= (4+2)*V
4+0= 6V
4=6V
V= 4/6
V= 0.6m/s
Hence the common velocity is 0.6m/s
Ответ: