adrianayepez8
05.05.2020 •
Physics
How far, and in what direction, should a cellist move her finger to adjust a string's tone from an out-of-tune 453 Hz to an in-tune 440 Hz? The string is 68.0 cm long, and the finger is 18.3 cm from the nut for the 453-Hz tone. (Assume the tone comes from the portion of the string between the cellist's finger and the end opposite the nut. Assume the string vibrates in the fundamental mode. Take the direction towards the nut to be positive. Indicate the direction with the sign of your answer.)
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Ответ:
She should move her finger 14 cm towards the nut
Explanation:
First of all let's find the velocity with the given wavelength and initial frequency (the outtune one ).
The formula is;
Velocity = Wavelength x frequency
We are given;
Since the string is 68.0 cm long, and the finger is 18.3 cm from the nut . Thus wavelength = 68 - 18.3 = 49.7cm = 0.497m
The outtune frequency is 453 Hz
Thus;
velocity = 0.497*452
Velocity = 224.644 m/s
We will now use this velocity in the same equation, but substitute the frequency value for the intune one and then use the new wavelength to tell where the cellist should move her finger
Thus;
velocity = wavelength*frequency
Wavelength = velocity/frequency
Thus;
wavelength = 224.644/440
Wavelength = 0.511 m
Difference between the 2 wavelengths is;
0.511m - 0.497m = 0.014m or 14cm (distance)
Since the string is actually increasing, she should move her finger 14 cm towards the nut
Ответ:
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