How far could an object go in three minutes if it starts at 2 m/s but speeds up to 19 m/s

1898.94 meters

Explanation:

Use kinematics.  First, we need to use the equation v(f) = v(i) + at.  The final velocity is 19 m/s, the initial velocity is 2 m/s, and the time is 120 seconds (it must be in seconds, so do 3 minutes*60).  19=2+a(180), solve for acceleration.

After solving, the acceleration equals .094 m/s².  Next, we need to find the distance, so we will use the kinematics equation v(f)² = v(i)² + 2ad.  Final velocity is 19 m/s, initial is 2 m/s, and the acceleration is .094 m/s².  19²=2²+2(.094)(d), solve for distance.

Distance = 1898.94 meters.

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