How far will a train with a speed of 20 m/s travel in: 10s
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Ответ:
Distance is equal to S/T
So
D=20/10
D=2m
Ответ:
constant horizontal force developed in the coupling C = 11.25KN
the friction force developed between the tires of the truck and the road during this time is 33.75KN
Explanation:
See attached file