How many joules of heat must be transferred to a 410-g aluminum pizza pan to raise its temperature from 32oC to 232oC? The specific heat of aluminum in this temperature range is 0.96 J/g x oC.
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Ответ:
recall that heat absorbed released is given by
Q = mc*(T2 - T1)
where
m = mass (in g)
c = specific heat capacity (in J/g-k)
T = temperature (in C or K)
*note: Q is (+) when heat is absorbed and (-) when heat is released.
substituting,
Q = (480)*(0.97)*(234 - 22)
Q = 98707 J = 98.7 kJ
Explanation:
Ответ:
A=48 CM2
Explanation:
A=9 X 10
A=90 CM2 9-2=7
A=6 X 7
A=42 CM2
A=90-42
A=48CM2