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YARETZYVENCES2144
10.05.2020 •
Physics
How many times louder is the intensity of sound at a rock concert in comparison with that of a whisper, if the two intensity levels are 110dB and 3dB, respectively?
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Ответ:
5 × 10¹⁰ or 5 billion times louder is the intensity of sound at a rock concert in comparison with that of a whisper
Explanation:
Given that at a rock concert;
the intensity of sound is 110 dB compared to a whisper of 3 dB
Now; how many times louder will that of the whisper be compared to the sound of the rock concert
Using the formula for calculating decibels (dB);
For 110 dB
dB = 10log₁₀(W)
110 dB =![10^{(110/10)}](/tpl/images/0652/7769/7f8e3.png)
110 dB = 10¹¹
For 3dB
dB = 10log₁₀(W)
3 dB =![10^{(3/10)}](/tpl/images/0652/7769/c82cb.png)
3 dB = 2
Now:
(110/3)dB = 10¹¹/2
(110/3)dB = 5 × 10¹⁰ or 5 billion times louder is the intensity of sound at a rock concert in comparison with that of a whisper
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