How much power is requiered to do 100j of work on time of 0.5 seconds
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Ответ:
Answer is 200 W
Explanation:
p= w/t= 100 j/ 0.5 s= 200 w
Ответ:
False
Explanation:
The net force is equal to the applied force minus the force of friction. It is possible for friction to act in the same direction as an applied force, but that would mean there would have to be more than two forces acting on the object.