How much thermal energy is absorbed by
1.00X102 g of ice at -20.0°C to become
water at 0.0°C?
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Ответ:
4202.4 J
Explanation:
The formula for calculating the heat absorbed by ice to melt into water is given by :
ΔH = Cp × m × Δ T where ;
Cp =specific heat of ice = 2.06 J/g° C
m= mass of ice = 102 g
ΔT = 0°C--20°C = 20°C
Thermal energy absorbed by the ice will be;
ΔH = Cp × m × Δ T
ΔH = 2.06 * 102 * 20
ΔH =4202.4 J
Ответ: