I need help with these. Please show workings

Imp = 25 [kg*m/s]

v₂= 20 [m/s]

Explanation:

In order to solve these problems, we must use the principle of conservation of linear momentum or momentum.

1)

where:

m₁ = mass of the object = 5 [kg]

v₁ = initial velocity = 0 (initially at rest)

F = force = 5 [N]

t = time = 5 [s]

v₂ = velocity after the momentum [m/s]

2)

Hey There!_____________________________________Question 1)_____________________________________DATA:

Force = F = 5N

time = t = 5 seconds

mass = m = 5 kg

momentum = p = ?

_____________________________________SOLUTION: IMPULSE FORCE:

The force which acts for a very short period of time is called impulse force. It is given by,

                                      I = F x t

Where,

              I is impulse

              F is force

              t is time till which force is exerted

The impulse experienced by the object equals the change in momentum of the object. In equation form,

                                    F x t = M x ΔV

 So,

                     F x t = Final momentum - initial momentum

                     F x t = final momentum - (0)

initial momentum is zero because the object was initially at rest.

                     Final momentum = 5 x 5

                     Final momentum = 25

So B is the answer

_____________________________________Question 2) _____________________________________DATA:

Force = F = 30 N

time = t = 0.05 seconds

mass = m = 0.075 kg

V = ?

_____________________________________SOLUTION:

impulse force is given by,

                                      I = F x t

Where,

              I is impulse

              F is force

              t is time till which force is exerted

The impulse experienced by the object equals the change in momentum of the object. So,

                                    F x t = M x ΔV

 So,

                     F x t = Final momentum - initial momentum

                     F x t = final momentum - (0)

Since it was at rest initially, initial momentum is zero.

Momentum is given by,

                                p = m x V

where,

           p is momentum

           m is mass

           v is velocity

So,

                 F x t = m x V

Rearrange the equation,

                                        V =

                                       

So C is the answer

_____________________________________Best Regards,'Borz'

Step-by-step explanation:

Two triangles are congruent by AAS postulate if two adjacent corresponding angles are congruent and the next adjacent sides to any of the angles is are also congruent. The adjacent sides should not be in between the two congruent angles.

From the triangles RQS and UTV

The adjacent side to is RQ and for is UT.

Similarly, the adjacent side to is QS and for is TV.

So, the possible sides that could be congruent by AAS postulate are:

or

So, the correct option is