If 3.61 m3 of a gas initially at stp is placed under a pressure of 2.67 atm , the temperature of the gas rises to 37.9 ∘c. what is the volume?

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas at STP = 1 atm

= final pressure of gas = 2.67 atm

= initial volume of gas =

= final volume of gas = ?

= initial temperature of gas at STP =

= final temperature of gas =

Now put all the given values in the above equation, we get:

Thus the final volume will be

8m/s

Explanation:

Given parameters:

Initial velocity  = 0m/s

Acceleration  = 4m/s²

Distance  = 8m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we use the right motion equation and find the unknown.

The right motion equation to solve this problem is given as :

        v²  = u²  + 2aS

v is the final velocity

u is the initial velocity

 a is the unknown acceleration

S is the distance

     Now insert the parameters and solve;

             v²  = 0² + 2 (4) (8)

             v² = 64

             v = 8m/s