If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 26m/s, how far would she travel during the race (in the same amount of time)?

34.45m

Explanation:

Using the equation of motion formula v² = u²+2as to get the distance travelled

v is the final velocity = 26m/s

u is the initial velocity = 0m/s

a is the acceleration due to gravity = 9.81m/s²

S is the distance travelled

Substituting the given values into the formula;

26² = 0²+2(9.81)s

676 = 0 + 19.62s

19.62s = 676

s = 676/19.62

s = 34.45m

Hence the distance she would travel during the race is 34.45m

1. You need two points because changes in temperature changes are not constant across measurement units. For example, a change of 10° Celcius is different from a change in 10° Fahrenheit.

2a. I believe that this means that temperature scale is constant/proportional to the length of the thermostat.

i. 2 milimeters

ii. 218 milimeters