If a block is in equilibrium the magnitude of the block's acceleration is
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Ответ:
If a block is in equilibrium the magnitude of the block's acceleration is 0m/s²
According to Newton's second law, the force acting on a body is equal to the product of its mass and acceleration.
Mathematically F = ma where:
m is the mass of the object
a is the acceleration of the object
If a block is in equilibrium, the magnitude of the force acting on the block will be 0, that is F = 0
Substituting F = 0 into the formula above to calculate the acceleration;
F = ma
0 = ma
Swap sides
ma = 0
a =0/m
a = 0m/s²
This shows that if a block is in equilibrium the magnitude of the block's acceleration is 0m/s²
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Ответ:
zero.
Explanation:
The condition for an object to be in equilibrium is that there is no resulting force acting on it, in other words, that the force on the object is zero:
and by Newton's second law we know that
where
is the mass of the object, and
its acceleration.
So combining the two things:
⇒
, This equation is fulfilled when ![a=0](/tpl/images/0061/5707/5c876.png)
Wich tells us that for the the block to be in equilibrium, the acceleration must be zero:
Ответ:
i guess c if not its a
Explanation: