Physics: If a car s acceleration is 600 m/s^2 and its time is 3 seconds, what is its δv? ( explain)

If a car s acceleration is 600 m/s^2 and its time - id60024115758, miahbaby2003p2af1b

Ответ:

Luciano3202

12.01.2022

Physics

The velocity required to accelerate the object is 1800 m/s.

Explanation:

When the velocity of an object changes rapidly, the object is said to be accelerating.

Acceleration can be defined as the rate of change of velocity with respect to time.

It can be formulated as,

$\begin{aligned}&a=\lim \left(\frac{\Delta v}{\Delta t}\right)=\left(\frac{d v}{d t}\right)\\&\Delta t \rightarrow 0\end{aligned}$

$a=\left(\frac{d v}{d t}\right)=\left(\frac{d}{d t}\right) \cdot\left(\frac{d s}{d t}\right)=\left(\frac{d^{2} s}{d t^{2}}\right)$

Given:

Acceleration = 600 m/s^2

Time = 3 seconds

$\begin{array}{l}{a=\left(\frac{d v}{d t}\right)} \\ \\{600=\left(\frac{\Delta v}{3}\right)} \\ \\{\Delta v=600 \times 3=1800 \mathrm{m} / \mathrm{s}}\end{array}$

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Ответ:

faithkristi

27.02.2022

Physics

Distance = 360 mi= 579.36 Km

Explanation:

Time taken: 3.5 hrs

Speed: 120mi/HR

Now we know that

distance = speed x time

Substituting the given values in the above formula we get

Distance= 120mi/hr x 3 hrs

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If a car's acceleration is 600 m/s^2 and its time is 3 seconds, what is its δv? ( explain)

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