If a silver wire has a resistance of 4.50 ohms at 20.0 degrees celsius, what is the temperature at which it will have 5.00 ohms resistance?

49.24 °C

Explanation:

R₀ = Resistance of the silver wire at 20.0 °C, = 4.50 Ω

T₀ = initial temperature of the silver wire = 20.0 °C

R = Resistance of the silver wire at temperature "T" = 5 Ω

T = Final temperature of silver wire

α = Temperature coefficient of resistance = 0.0038 °C

Using the equation

R = R₀ (1 + α (T - T₀))

Inserting the values

5 = (4.50) (1 + (0.0038) (T - 20))

T = 49.24 °C

The input work = Force x distance
So I/P = 45 x 1.5 = 67.5 N.m

The output work = Force x distance
So, O/P = 87.6 x 0.4 = 35.04 N.m

Efficiency = (output work / Inputwork) x 100
= ( 35.04/67.5) x100

Efficiency = 51.91 %